# Sum of the digits using break

Write a program that reads a number and prints the sum of its digits. Use the division (/) operator and the remainder (%) operator. It is similar to the previous program and use break.

#include<iostream>
using namespace std;
int main(){
int n,sum=0,d;
cout<<"Enter the number : ";
cin>>n;
while(true){
d = n%10;
sum = sum + d;
n = n/10;
if(n==0) break;
}
cout<<"The sum is "<<sum<<endl;
return 0;
}

Here, d gets the remainder. The remainder is added to the sum. Then n is reduced by 10. This is done till n becomes 0 and it gets out of loop.